Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.1 Counting - 13.1 Asses Your Understanding - Page 847: 26

Answer

$80000.$

Work Step by Step

According to the Multiplication Principle, if we have $p$ selections for the first choice, $q$ selections for the second choice, then we have $p\cdot q$ different ways of selections. (similarly for more than two choices). For the first digit we have $8$ selections and for the rest we have $10$, hence $8\cdot10\cdot10\cdot10\cdot10=80000.$
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