Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 806: 1

Answer

$f(2)=\dfrac{1}{2}$ $f(3)=\dfrac{2}{3}$

Work Step by Step

If $f(x)=\frac{x-1}{x}$, then for $f(2)$ I substitute $x=2$ hence, $f(2)=\frac{2-1}{2}=\frac{1}{2}$ For $f(3)$, I substitute $x=3$ hence $f(3)=\frac{3-2}{3}=\frac{2}{3}$
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