Answer
$x=5.$
Work Step by Step
$\sqrt{3x+1}=4.\\(\sqrt{3x+1})^2=4^2\\3x+1=16\\(3x+1)-1=16-1\\3x=15\\\frac{3x}{3}=\frac{15}{3}\\x=5.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 11 - Systems of Equations and Inequalities - Chapter Review - Cumulative Review - Page 797: 2
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