Answer
$y=\pm\dfrac{4}{9}x$
Work Step by Step
For the hyperbola $\dfrac{y^2}{16}-\dfrac{x^2}{81}=1$, the asymptotes are:
$y-0=\pm\dfrac{\sqrt{16}}{\sqrt{81}}(x-0)$
$y=\pm\dfrac{4}{9}x$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 10 - Analytic Geometry - 10.4 The Hyperbola - 10.4 Assess Your Understanding - Page 669: 14
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