Answer
False
Work Step by Step
Since the $e^x$ function grows faster than $x^3$, the denominator for $\frac{1}{e^x}$ will also grow faster. Thus, this function will approach zero faster than $ \frac{1}{x^3}$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 11 - Polynomial and Rational Functions - Strengthen Your Understanding - Page 489: 13
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