Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test - Page 324: 20

Answer

$14\frac{1}{40}$

Work Step by Step

$3\frac{7}{8}+7\frac{2}{5}+2\frac{3}{4}$ $=3\frac{7}{8}+2\frac{6}{8}+7\frac{2}{5}$ $=5\frac{13}{8}+7\frac{2}{5}$ $=6\frac{5}{8}+7\frac{2}{5}$ $=6\frac{25}{40}+7\frac{16}{40}$ $=13\frac{41}{40}$ $=14\frac{1}{40}$
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