Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Group Activity - Lobster Classification - Page 313: 3

Answer

Maximum weight $=8\frac{1}{4}$ pounds Minimum weight $=6\frac{1}{4}$ pounds

Work Step by Step

Maximum weight: $1\frac{1}{8} + 1\frac{1}{8} + 2\frac{1}{2} + 3\frac{1}{2}$ $= 2\frac{2}{8} + 6$ $=8\frac{2}{8}$ $=8\frac{1}{4}$ Minimum weight: $ 1 + 1 + 1\frac{3}{4} + 2\frac{1}{2}$ $= 3\frac{3}{4} + 2\frac{1}{2}$ $= 6\frac{1}{4} $
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