Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set - Page 275: 92

Answer

2 inches

Work Step by Step

First, the lowest common denominator of the three fractions that make up the width is found. 16 is the lowest number divisible by 16 and 8, so it is the LCD. Next, the fractions are multiplied so that their denominators are equal to the LCD. The first dimension, $\frac{11}{16}$ inches, already has the LCD as its denominator, so it is not necessary to multiply it by anything, the second dimension, $\frac{5}{8}$, is multiplied by 2, so that it is now equal to $\frac{10}{16}$, and the third fraction, $\frac{11}{16}$, also already has the LCD as its denominator, so it is not necessary to multiply it by anything. The three new fractions we have, $\frac{11}{16}$, $\frac{10}{16}$ and $\frac{11}{16}$, are added together to get a sum of $\frac{32}{16}$, which when simplified is equal to 2. Therefore, the width marked in the diagram is equal to 2 inches.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.