Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 321: 74

Answer

$1\frac{1}{2}$ ft

Work Step by Step

Sum the lengths of the sides. $\frac{1}{5}+\frac{3}{5}+\frac{7}{10}=\frac{1\times2}{5\times2}+\frac{3\times2}{5\times2}+\frac{7}{10}=\frac{2}{10}+\frac{6}{10}+\frac{7}{10}=\frac{2+6+7}{10}=\frac{15}{10}$ Reduce. $\frac{15}{10}=\frac{15\div5}{10\div5}=\frac{3}{2}=1\frac{1}{2}$
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