Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - 7.4 Linear Inequalities in Two Variables - Exercise Set 7.4 - Page 454: 43

Answer

See below:

Work Step by Step

consider the provided inequalities, \[y>\frac{3}{2}x-2\]and\[y<4\] Replace each inequality symbol with an equal sign, \[y=\frac{3}{2}x-2\]and\[y=4\] Now, draw the graph of the equation\[y=\frac{3}{2}x-2\]: Put \[y=0\] for x-intercept and \[x=0\] for y-intercept in the equation \[y=\frac{3}{2}x-2\]. So, the x-intercept is \[\frac{4}{3}\] and y-intercept is \[-2\]. Therefore, the line is passing through \[\left( \frac{4}{3},0 \right)\]and \[\left( 0,-2 \right)\]. Now, consider a test point \[\left( 0,0 \right)\], which lies in the half-plane above the line. Substitute \[x=0\] and \[y=0\]in \[y>\frac{3}{2}x-2\]. \[\begin{align} & 0>\frac{3}{2}\cdot 0-2 \\ & 0>-2 \end{align}\] Since \[\left( 0,0 \right)\]satisfies the above inequality \[y>\frac{3}{2}x-2\]. So, the test point \[\left( 0,0 \right)\] is part of the solution set. All the points on the same side of the line \[y=\frac{3}{2}x-2\]as the point \[\left( 0,0 \right)\] are members of the solution set. Since,\[y>\frac{3}{2}x-2\] is not contain an equal sign. So, the line should be dotted. Now, draw the graph of the equation \[y=4\]: To draw the graph of the equation\[y=4\], draw a horizontal line with y-intercept 4. The line is dotted because equality is not included in \[y<4\]. Because of the less than part of \[
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