Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - 7.3 Systems of Linear Equations in Two Variables - Exercise Set 7.3 - Page 445: 44

Answer

The system of linear equations has infinitely many solutions and the solution set is\[\left\{ \left( x,y \right)|4x-2y=2 \right\}\].

Work Step by Step

The system of linear equation: \[\begin{align} & 4x-2y=2 \\ & 2x-y=1 \end{align}\] Multiply \[2\]on both sides to the equation\[2x-y=1\], and get: \[4x-2y=2\]. Subtract the second given equation to the above obtained equation from both RHS and LHS as follows: \[\underline{\begin{align} & 4x-2y=2 \\ & -4x+2y=-2 \end{align}}\] \[\ \ \ \ \ \ \ \ \ \ \ 0=0\] Since,\[0=0\] it implies that the system of linear equations has infinitely many solutions. The two lines coincide and all the points lying on the lines are the solution to the system of the linear equations. Therefore the solution set is\[\left\{ \left( x,y \right)|4x-2y=2 \right\}\]. Hence, the system of linear equations has infinitely many solutions and the solution set is \[\left\{ \left( x,y \right)|4x-2y=2 \right\}\].
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