Answer
(4x+1)(2x-3)
Work Step by Step
$8x^{2}$ - 10x -3 = (4x+1) (2x__)
step 1. Find two first terms whose product is $8x^{2}$
$8x^{2}$ - 10x -3 = (4x+1) (2x__) which is given and
Step 2. To find the second term of each factor, we must find two integers whose product is -3 and whose sum is -10
List pairs of factors of the constant, -3
(1,-3)(-1,3)
step 3. The correct factorization of $8x^{2}$ - 10x -3 is the one in which the sum of the Outside and Inside products is equal to -10x.
list of the possible factorization :
(4x-1)(2x+3) = $8x^{2}$ +10x -3
(4x+1)(2x-3) =$8x^{2}$ - 10x -3
So, (4x+1)(2x-3) is the solution
