Answer
\[\left\{ x|x\le 14 \right\}\]
Work Step by Step
Let us suppose the number is\[x\].
Then, the algebraic form of the inequality is
\[2\left( 4+x \right)\le 36\]
Now, find out possible values of \[x\] satisfying the inequality and the inequality is solved as follows:
\[\begin{align}
& 2\left( 4+x \right)\le 36 \\
& 4+x\le 18 \\
& x\le 14 \\
\end{align}\]
Hence, all the real numbers less than or equal to 14 will satisfy the condition.
The set-builder form of the inequality is obtained as follows:
\[\left\{ x|x\le 14 \right\}\]