Answer
See below
Work Step by Step
Let $x$ be the amount of years passed.
Then our equation is: $13300+1000x=26800-500x\\1500x=13500\\x=9$
So we they will be equal in $9$ years, in $2019$ and they both will have $13300+1000(9)=22300$ students.
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 6 - Algebra: Equations and Inequalities - 6.3 Applications of Linear Equations - Exercise Set 6.3 - Page 375: 35
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