Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.1 Algebraic Expressions and Formulas - Exercise Set 6.1 - Page 348: 66

Answer

$14x^{2}$ - 11

Work Step by Step

4($6x^{2}$ -3) - [2($5x^{2}$ - 1) + 1] Step 1: Drop parentheses and multiply 4 and 2with each term and change the sign of each term in parentheses: 4($6x^{2}$ -3)) = $24x^{2}$ -12 and 2($5x^{2}$ - 1)= $10x^{2}$ - 2 Step 2 Simplify inside brackets: -2+1 = -1 $24x^{2}$ -12- [$10x^{2}$ - 1] Step 3 drop brackets and change the sign of each term in brackets $24x^{2}$ -12- $10x^{2}$ + 1 Step 4: Group like terms($24x^{2}$ - $10x^{2}$ ) - 12+1 Step 6: Combine the like terms ($24x^{2}$ - $10x^{2}$ ) = $14x^{2}$ So, final solution $14x^{2}$ - 11
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