Answer
\[-\frac{19}{2}\]
Work Step by Step
As grouping symbol is there, perform the operation inside the parenthesis and then subtract as follows:
\[\begin{align}
& \left( \frac{1}{2} \right)-8\left( \frac{1}{4}+1 \right)=\left( \frac{1}{2} \right)-8\left( \frac{5}{4} \right) \\
& =\left( \frac{1}{2} \right)-\left( \frac{40}{4} \right) \\
& =\frac{2-40}{4} \\
& =-\frac{38}{4}
\end{align}\]
Evaluate further as:
\[\begin{align}
& \left( \frac{1}{2} \right)-8\left( \frac{1}{4}+1 \right)=-\frac{38}{4} \\
& =-\frac{19}{2}
\end{align}\]
Hence, the value of the provided expression is\[-\frac{19}{2}\].
