Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 299: 107

Answer

$\sqrt2-\sqrt2=0$

Work Step by Step

THe given statement is false because $\sqrt2 - \sqrt2 = 0$ and $0$ is not an irrational number.
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