Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 296: 60

Answer

$6\sqrt5$

Work Step by Step

Rationalize the denominator by multiplying $\sqrt5$ to both the numerator and denominator: $=\dfrac{30\sqrt5}{\sqrt5(\sqrt5)} \\=\dfrac{30\sqrt5}{5}$ Cancel the common factor, 5, to find: $=6\sqrt{5}$
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