Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.5 Survey Problems - Exercise Set 2.5 - Page 103: 29

Answer

The number of elements for the different asked regions is shown below:

Work Step by Step

Simplify region II: \[n\left( A\cap B \right)=17\]is equal to region II\[+\]V. \[\begin{align} & \text{II}+\text{V}=17 \\ & \text{II}+7=17 \\ & \text{II}=10 \end{align}\] For region IV: \[n\left( A\cap C \right)=11\]is equal to region IV\[+\]V. \[\begin{align} & \text{IV}+\text{V}=11 \\ & \text{IV}+7=11 \\ & \text{IV}=4 \end{align}\] For region VI: \[n\left( B\cap C \right)=8\]is equal to region VI\[+\]V. \[\begin{align} & \text{VI}+\text{V}=8 \\ & \text{VI}+7=8 \\ & \text{VI}=1 \end{align}\] For region I: \[n\left( A \right)=26\]is equal to region I\[+\]II\[+\]IV\[+\]V. \[\begin{align} & \text{I}+\text{II}+\text{IV}+\text{V}=n\left( A \right) \\ & 10+4+7+\text{I}=26 \\ & \text{I}=26-21 \\ & \text{I}=5 \end{align}\] For region III: \[n\left( B \right)=21\]is equal to region II\[+\]III\[+\]V\[+\]VI. \[\begin{align} & \text{II}+\text{III}+\text{V}+\text{VI}=n\left( B \right) \\ & 10+7+1+\text{III}=21 \\ & \text{III}=21-18 \\ & \text{III}=3 \end{align}\] For region VII: \[n\left( C \right)=18\]is equal to region IV\[+\]V\[+\]VI\[+\]VII. \[\begin{align} & \text{IV}+\text{V}+\text{VI}+\text{VII}=n\left( C \right) \\ & 4+7+1+\text{VII}=18 \\ & \text{VII}=18-12 \\ & \text{VII}=6 \end{align}\] For region VIII: \[\begin{align} & \text{VIII}=38-n\left( A\cup B\cup C \right) \\ & =38-\left( 5+10+4+3+7+1+6 \right) \\ & =38-36 \\ & =2 \end{align}\]
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