Answer
{$\frac{4}{7}$,$\frac{9}{13}$} ⊄ {$\frac{7}{4}$,$\frac{13}{9}$}
Work Step by Step
As no element of first set is present in the second set,
Therefore
{$\frac{4}{7}$,$\frac{9}{13}$} ⊄ {$\frac{7}{4}$,$\frac{13}{9}$}
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 2 - Set Theory - 2.2 Subsets - Exercise Set 2.2 - Page 68: 11
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