Answer
See below.
Work Step by Step
a) $(2(1)+4)/2-2=1$
$(2(2)+4)/2-2=2$
$(2(3)+4)/2-2=3$
$(2(4)+4)/2-2=4$
$(2(5)+4)/2-2=5$
Conjecture: the result is the original number.
b) Proof: for any $n$, the procedure is as follows:
$n$, then $2n$, then $2n+4$, then $(2n+4)/2=n+2)$, then $(n+2)-2=n$, thus we always get back the original number.