Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapters 1-6 - Cumulative Review Exercises - Page 474: 24

Answer

$\frac{1}{4}$

Work Step by Step

We have $$(\frac{5}{6} - \frac{5}{12}) - (\frac{1}{2})^2 * \frac{2}{3}$$ Doing the subtraction and the square power $$\frac{10-5}{12} - \frac{1}{4}*\frac{2}{3}$$ Doing the multiplication $$\frac{5}{12} - \frac{1}{6}$$ Finally solving the subtraction $$\frac{5-2}{12}= \frac{3}{12} = \frac{1}{4}$$
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