Answer
a)
Frontage: 175 yd
b)
Area of the Lot: 8750 yd$^{2}$
Work Step by Step
a)
The distance bordering the street is:
75 yd + 100 yd = 175 yd
b)
To find the total area of the shape we must break it into a triangle on the left and a rectangle on the right.
Area of a Triangle: $A$$_{tri}$ = $\frac{1}{2}$$b$$h$
Area of a Rectangle: $A$$_{rec}$ = $l$$w$
$A$$_{tri}$ = $\frac{1}{2}$(75 yd)(100 yd)
$A$$_{tri}$ = 3750 yd$^{2}$
$A$$_{rec}$ = (100 yd)(50 yd)
$A$$_{rec}$ = 5000 yd$^{2}$
$A$$_{total}$ = $A$$_{tri}$ + $A$$_{rec}$
$A$$_{total}$ = 3750 yd$^{2}$ + 5000 yd$^{2}$
$A$$_{total}$ = 8750 yd$^{2}$