Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 566: 4

Answer

Area of the Triangle = $A$ = 52 yd$^{2}$ Perimeter of the Triangle = $P$ = 34 yd

Work Step by Step

Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(13 yd)(8 yd) $A$ = 52 yd$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 9 yd + 12 yd + 13 yd $P$ = 34 yd
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