Chapters 1-9 - Cumulative Review Exercises - Page 703: 19

Name of the figure $=$ square Perimeter $= 9$ ft Area $ \approx 5.1$ sq ft

1. Name of the figure Square ($4$ equal sides) 2. Perimeter Let $P =$ perimeter of the square $P = 4 \times 2.25$ (Note that $2.25 = 2\frac{1}{4}$) $P = 9$ ft 3. Area Let $A =$ area of the square $A = 2.25 \times 2.25$ $A = 5.0625$ ft$^{2}$ $A \approx 5.1$ ft$^{2}$