Answer
$= (-\frac{1}{3})^{2}+(\frac{1}{4})(-\frac{4}{9}) = 0$
Work Step by Step
$= (-\frac{1}{3})^{2}+(\frac{1}{4})(-\frac{4}{9})$
$= (\frac{1}{9})-(\frac{4}{36})$
$= (\frac{1}{9}) - (\frac{1}{9})$
$=0$
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