Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises - Page 689: 54

The length of the house is $33$ ft and the width of the house is $28$ ft.

Let $x = $ the length of the house $2(x -5) + 2(x) = 122$ $2x - 10 + 2x = 122$ $4x - 10 = 122$ $4x = 132$ $x = \frac{132}{4}$ $x = 33$ ft Let $y = $ the width of the house $y = (x - 5)$ $y = 33 - 5$ $y = 28$ ft