Answer
$5x-20$, $-8y+16$
Work Step by Step
The distributive property holds that $a(b+c)=ab+ac$.
A. Therefore, $5(x-4)=(5\times x)+(5\times-4)=(5x)+(-20)=5x-20$.
In this example, the student has forgotten to distribute the 5 to the second term in parentheses.
B. Therefore, $-8(y-2)=(-8\times y)+(-8\times-2)=(-8y)+(16)=-8y+16$.
In this example, the student has forgotten that multiplying the negative number outside of the parentheses by the negative second term will result in a positive product.
