Answer
No
Work Step by Step
We can plug in $r=-2$ to the equation to see if it is a solution.
$6r-3=6(-2)-3=6\times-2-3=-12-3=-15\ne-14$
Therefore, $r=-2$ is not a solution to the given equation.
Basic College Mathematics (10th Edition)
by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.
Published by
Pearson
ISBN 10:
0134467795
ISBN 13:
978-0-13446-779-5
Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 668: 6
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