Answer
A = $\frac{55}{2}$ $yd^{2}$ or 27$\frac{1}{2}$ $yd^{2}$
Work Step by Step
A = $\frac{1}{2}$bh
b =15 ft, h = 3 ft
In this formula, b is the length of the base of the triangle and h is the height of the triangle. What is the area if b is 5 yd and h is 11 yd?
A = $\frac{1}{2}$bh
Evaluate the formula by replacing b with 5 yd and h with 11 yd.
A = $\frac{1}{2}$ * 5 yd * 11 yd
= $\frac{55}{2}$ $yd^{2}$
Convert it into mixed fraction
27$\frac{1}{2}$ $yd^{2}$
The area of the triangle is $\frac{55}{2}$ $yd^{2}$ or 27$\frac{1}{2}$ $yd^{2}$
