Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.4 Order of Operations - 9.4 Exercises - Page 653: 38

Answer

53

Work Step by Step

$5(4^{2})-6(1+4)-(-3)$ 1. Solve inside the parenthesis first, so: $5(16) -6(5)-(-3)$ 2. When 2 negatives multiply, they become positive: $5(16) -6(5)+3$ 3. Expand the parenthesis: $80 -30+3 = 53$
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