Answer
The perimeter is $37.8$ yd and the area is $58.5$ sq yd.
Work Step by Step
1. Find the perimeter of the triangle
Let $P =$ the perimeter of the triangle
$P = 9 + 13 + 15.8$
$P = 37.8$ yd
2. Find the area of the triangle
Let $A =$ the area
$A = (9 \times 13) \div 2$
$A = 117 \div 2$
$A = 58.5$ sq yd
