Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.6 Circles - 8.6 Exercises - Page 575: 27

Answer

Area of Watch: 0.8 in$^{2}$ Circumference of Watch: 3.1 in Area of Clock: 28.3 in$^{2}$ Circumference of Clock: 18.8 in

Work Step by Step

Area of a Circle: $A$ = $\pi$$r$$^{2}$ Area of a Circle: $A$ = $\pi$$d$$^{2}$/4 Circumference of a Circle: $\pi$$d$ Circumference of a Circle: 2$\pi$$r$ Therefore: $A$$_{watch}$ = (3.14)(1 in)$^{2}$ / 4 $A$$_{watch}$ = 0.8 in$^{2}$ $C$$_{watch}$ = (3.14)(1 in) $C$$_{watch}$ = 3.1 in $A$$_{clock}$ = (3.14)(3 in)$^{2}$ $A$$_{clock}$ = 28.3 in$^{2}$ $C$$_{clock}$ = 2(3.14)(3 in) $C$$_{clock}$ = 18.8 in
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