Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 566: 28

Answer

Total area of nylon needed: 23.50 ft$^{2}$

Work Step by Step

To find out how much fabric is needed we must add the areas of all the triangles together. $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$$_{total}$ = ($\frac{1}{2}$(3 ft)(3.5 ft)) +($\frac{1}{2}$(3 ft)(3.5 ft)) + ($\frac{1}{2}$(4 ft)(6.5 ft)) $A$$_{total}$ = 5.25 ft$^{2}$ + 5.25 ft$^{2}$ + 13 ft$^{2}$ $A$$_{total}$ = 23.50 ft$^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.