Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 552: 25

Answer

$$2450 \ yd^2$$

Work Step by Step

We know the following equation: $$ A= w \times l$$ Thus, for the smaller field: $$ A =65 \times 110 \\ A = 7150 \ yd^2$$ For the larger field: $$ A = 80 \times 120 \\ A = 9600 \ yd^2$$ Therefore, the difference is: $$ 9600 - 7150 \\ = 2450 \ yd^2$$
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