Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 551: 21

Answer

$$100.4 \ in^2$$

Work Step by Step

We know the following equation: $$ A= w \times l$$ Thus, for the laptop: $$ A = 12.9 \times 9 \\ A = 116.1 \ in^2$$ For the phone: $$ = 5.6 \times 2.8 \\ = 15.7\ in^2$$ Thus, the difference is: $$ = 116.1\ in^2 - 15.7 \ in^2 \\ = 100.4 \ in^2$$
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