Answer
(a) 96.0% have a smoke alarm
(b) 45.9% have a carbon monoxide detector
Work Step by Step
$\frac{part}{whole}=\frac{percent}{100}$
(a) 965 out of 1005 have a smoke alarm
$\frac{965}{1005}=\frac{p}{100}$
cross multiply to solve for p
$1005p=(965)(100)$
$1005p\div1005=96500\div1005$
$p=96.0199$
(b) 461 out of 1005 have a carbon monoxide detector
$\frac{461}{1005}=\frac{p}{100}$
cross multiply to solve for p
$1005p=(461)(100)$
$1005p\div1005=46100\div1005$
$p=45.8706$
