Answer
$\frac{13}{48}$
Work Step by Step
$(\frac{3}{4})^{2} -(\frac{7}{8}.\frac{1}{3}) $
= $(\frac{3}{4}\times\frac{3}{4}) - (\frac{7\times1}{8\times3})$ (First Solve Bracket)
= $(\frac{9}{16}) - (\frac{7}{24})$
= $\frac{9\times3}{16\times3} - \frac{7\times2}{24\times2} $ (Least common multiple of 16 & 24 is 48)
= $\frac{27}{48} - \frac{14}{48}$
= $\frac{27-14}{48}$
= $\frac{13}{48}$
