Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - Test - Page 259: 11

Answer

$\frac{1}{40}$

Work Step by Step

$\frac{2}{5}-\frac{3}{8}=\frac{2\times8}{5\times8}-\frac{3\times5}{8\times5}=\frac{16}{40}-\frac{15}{40}=\frac{16-15}{40}=\frac{1}{40}$
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