Answer
$2\frac{1}{6}$
Work Step by Step
$6\frac{2}{3}-4\frac{1}{2}$
Now. convert mixed fractions into improper fractions,
= $\frac{6\times3+2}{3}-\frac{4\times2+1}{2}$
= $\frac{20}{3}-\frac{9}{2}$
now the least common multiple of 3 & 2 is 6. so multiply the nominator and denominator of first fraction with 2 and second fraction by 3.
$\frac{20\times2}{3\times2}-\frac{9\times3}{2\times3}$
= $\frac{40}{6}-\frac{27}{6}$
Subtract numerators, as all fractions have same denominator
= $\frac{40-27}{6}$
= $\frac{13}{6}$
= $2\frac{1}{6}$
