Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 243: 19

Answer

$\frac{11}{18}\gt\frac{5}{9}$

Work Step by Step

We can rewrite $\frac{5}{9}=\frac{5\times2}{9\times2}=\frac{10}{18}$. $\frac{11}{18}$ is greater than $\frac{10}{18}$, because its numerator is greatest while both denominators are the same Therefore, $\frac{11}{18}\gt\frac{5}{9}$.
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