Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.5 - 3.5 Exercises - Page 246: 73

Answer

$\frac{2}{45}$

Work Step by Step

$(\frac{2}{3})^{2} - (\frac{4}{5} - \frac{3}{10}) \div \frac{5}{4}$ = $\frac{4}{9} - (\frac{8}{10} - \frac{3}{10}) \div \frac{5}{4}$ = $\frac{4}{9} - \frac{5}{10} \div \frac{5}{4}$ = $\frac{4}{9} - \frac{5}{10} \times \frac{4}{5}$ = $\frac{4}{9} - \frac{20}{50}$ = $\frac{4}{9} - \frac{2}{5}$ = $\frac{20}{45} - \frac{18}{45}$ = $\frac{2}{45}$
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