Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 222: 47

Answer

3/16

Work Step by Step

To find the missing diameter, we subtract the entire length by the two lengths of the rectangle not included with the circle. Doing this, we find: $$ =\frac{15}{16} -\frac{3}{8}-\frac{3}{8} \\ =\frac{15}{16} -\frac{6}{16} - \frac{6}{16} \\ =\frac{3}{16} \\ $$
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