Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 221: 44

Answer

$\frac{17}{48}$ of the water remains.

Work Step by Step

$\frac{7}{8} - \frac{3}{16} - \frac{1}{3}$ Find the LCM using prime factorization. 8 = 2 x 2 x 2 16 = 2 x 2 x 2 x 2 3 = 3 LCM = 2 x 2 x 2 x 2 x 3 = 48 Express as like fractions then subtract. $\frac{7}{8} - \frac{3}{16} - \frac{1}{3}$ = $\frac{42}{48} - \frac{9}{48} - \frac{16}{48}$ = $\frac{17}{48}$
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