Answer
$\frac{63}{16}yd^{2}$ or $3\frac{15}{16}yd^{2}$
Work Step by Step
Area of rectangle = Length $\times$ width
= $4\frac{1}{2} yd\times\frac{7}{8} yd$
= $\frac{9}{2}\times\frac{7}{8} yd^{2}$
= $\frac{9\times7}{2\times8} yd^{2}$
= $\frac{63}{16}yd^{2}$ or $3\frac{15}{16}yd^{2}$ (Area of rectangle)
