Answer
$\frac{49}{32}in^{2}$
Work Step by Step
Area = Length $\times$ width
= $1\frac{3}{4}in \times \frac{7}{8}in$
= $\frac{7}{4} \times \frac{7}{8}in^{2}$
= $\frac{7\times7}{4\times8}in^{2}$ (multiply nominator and denominator)
= $\frac{49}{32}in^{2}$
