Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 10 - Statistics - Review Exercises - Page 752: 22

Answer

The weighted mean is 118.8

Work Step by Step

The weighted mean is the average of all the numbers in a set of numbers. If a number occurs multiple times it is counted that many times in the average. Sum the frequencies to find the total number of items in the set. $f=6+14+21+13+22+6+9=91$ Sum all the test scores and divide by the frequency count to find the weighted mean. $m=((104\times6)+(112\times14)+(115\times21)+(119\times13)+(123\times22)+(127\times6)+(132\times9))\div91$ =$(624+1568+2415+1547+2706+762+1188)\div91$ =$10810\div91$ =$118.8$
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