Answer
$x\approx2.4\text{ or }x\approx-2.4$
Work Step by Step
We start with the given equation: $5+x^2=11$
In order to get the term with $x$ by itself, we subtract $5$ from both sides of the equation: $$5-5+x^2=11-5$$$$x^2=6$$To solve the equation $x^2=6$, we must perform the opposite operation of squaring, which is taking the square root, in order to clear the exponent: $$x^2=6$$$$\sqrt {x^2}=\sqrt {6}$$$$x\approx\pm2.4$$$$x\approx2.4\text{ or }x\approx-2.4$$
