Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Common Core End-of-Course Assessment - Page 881: 43

Answer

$\bf{C}$

Work Step by Step

We are given that the $\triangle ABD$ is a $30^{\circ}-60^{\circ}-90^{\circ}$ This means: $AB=\sqrt 3BD$ Here, $BC=1 \ cm$, so we have $AB=\sqrt 3 \ cm$ Also, $\triangle ABC$ is a $30^{\circ}-60^{\circ}-90^{\circ}$ triangle. That is, $BC=\sqrt 3 AB$ Here, $BC=CD+1 \ cm$ and $AB=\sqrt 3 \ cm$, so we have $AB=\sqrt 3 \ cm$ $CD+1=(\sqrt 3)(\sqrt 3) \\ CD=2 \ cm$ Therefore, the correct option is $\bf{C}$.
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