Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - Chapter Test - Page 537: 8

Answer

sin B = $\frac{2\sqrt {57}}{22}$ or $\frac{\sqrt {57}}{11}$ cos B = $\frac{16}{22}$ or $\frac{8}{11}$ tan B = $\frac{2\sqrt {57}}{16}$ or $\frac{\sqrt {57}}{8}$

Work Step by Step

Let's set up the trigonometric ratios. The ratio for sine is: sin θ = $\frac{opposite}{hypotenuse}$ The ratio for cosine is: cos θ = $\frac{adjacent}{hypotenuse}$ The ratio for tangent is: tan θ = $\frac{opposite}{adjacent}$ Let's plug in our values: sin B = $\frac{2\sqrt {57}}{22}$ or $\frac{\sqrt {57}}{11}$ cos B = $\frac{16}{22}$ or $\frac{8}{11}$ tan B = $\frac{2\sqrt {57}}{16}$ or $\frac{\sqrt {57}}{8}$
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